Closed ucohen closed 5 years ago
should work as: df >>= mutate(nonans=fillna(X.col_with_nans, value_to_replace))
can be easily done via: @make_symbolic def fillna(series, val): return series.fillna(val)
Thanks!
should work as: df >>= mutate(nonans=fillna(X.col_with_nans, value_to_replace))