You're right. I will fix that. Thanks.
Rodrigo
On 12/14/2011 7:46 PM, Ciaran O'Reilly wrote:
> Hi Rodrigo,
>
> The logic for checking if something is a random variable appears to only work
if the random variable is mentioned explicitly in a factor of the model. For
example, from testMessageToVaraibleFromFactor() -
>
> ... ExampleModel.EMPTY_PQ, "message to [p(X)] from [if p(X) and q(Y) then 3
else 1]" ...
>
> [p(X)] is failing the test:
>
> BracketedExpressionSubExpressionsProvider.isRandomVariable() due to there
being no factors in the model.
>
> Let me know what you think.
>
> Thanks
Original issue reported on code.google.com by ctjoreilly@gmail.com on 11 Apr 2013 at 12:33
Original issue reported on code.google.com by
ctjoreilly@gmail.com
on 11 Apr 2013 at 12:33