Closed yezige closed 2 years ago
The following picture shows the debugging information, video id: vjbBaai9ZA8.
That's not a problem. Just pass the video and the format to client.GetStreamURL(video *Video, format *Format) to retreive the URL.
client.GetStreamURL(video *Video, format *Format)
OK, thanks
The following picture shows the debugging information, video id: vjbBaai9ZA8.