Indexer and simple recommender system

[seichris]

There are two problems:

1. How can one user see another user's bookmarks?
2. How can one user get recommendations on new bookmarks, based on bookmarks from another user?

There are two possible solutions:

1. Build a central service that reads all bookmarks. And runs a simple recommender algo on the data, eg. based on calculating similarities between users.
2. Users give access to their bookmarks p2p. So only them and their friends can see the bookmarks.

We want to test both approaches.

	Advantages now	Disadvantages now	Advantages later	Disadvantages later
1.	Scalable. We can give recommendations to everyone. Like a web2 app.	Centralized hurts privacy	but in the future we might be able to run algorithms on the data, without revealing the data (zk proofs). And we can build a data marketplace.	-
2.	Privacy	Not scalable	Privacy. P2p business	-

[seichris]

@dakingha69 do you have more thoghts? Does it make sense?

[dohaki]

@dakingha69 do you have more thoghts? Does it make sense?

No makes sense what you wrote 👍 . Maybe a bit more context would be, that we are using IDX for data discovery. So the bookmarks of a user are tied to a DID. With approach 1, we would then need to collect all user DIDs (with their consent) through our app/extension and generate the pool of bookmarks on which we can run our simple recommendation algo. Approach 2 would require a client-side solution that discovers bookmarks through connected/known DIDs of the respective user.

[seichris]

Which one is easier to build, for the MVP? @dakingha69

centralized service

Use case: A general pinboard-like popular feed, sorted by number of total shares.

the p2p one

Use case: tl;drs anywhere #5 // week-in-ethereum with comments #8

• receiver whitelisting = "following DIDs"

• receiver blacklisting = "blocking DIDs"

• sender whitelisting = "this user can read it (, because he paid for it)"

• sender whitelisting everyone = like a newsletter <<< would this need the centralized service setup anyway?