Open korenmiklos opened 8 months ago
If T1 wins in competition with T2 and T3, we learn that its rapport is Frechet with T1+T2+T3.
But 2 and 3 will "ask for a new draw" so that their loss is not persistent. They will remain Frechet with T2 and T3.
Another match will result in a win for 1 with prob (T1 + T2 + T3) / (T1 + 2 T2 + 2 T3).
This provides easy-to-follow dynamics. But have to measure the number of competitions and the participants.
win(T1, T2) = T1 + alpha * T2
rather thanT1 + T2