Now, when parser1 <|> parser2 is failed to parse, the result becomes Left ParseFailed[reason1, reason2].
But if either of these consists of choice((<|>), choice), the result becomes a nest of ParseFailed [].
It doesn't seem better method.
Does anyone be coming up with better way?
(ParseFailed may be used for generating compilation errors. So I wish it be meaningful for it.)
Roadagain
commented
7 years ago
Now, when
parser1 <|> parser2is failed to parse, the result becomesLeft ParseFailed[reason1, reason2]. But if either of these consists of choice((<|>),choice), the result becomes a nest ofParseFailed []. It doesn't seem better method.Does anyone be coming up with better way? (
ParseFailedmay be used for generating compilation errors. So I wish it be meaningful for it.)