Closed Jopie64 closed 4 years ago
Ok I figured out why the tests kept failing. It was because of something in the tests themselves. They succeed now (together with the fix). Can you still take a look at this commit? 10a2d2bec3d61b3fe51d1ca6e6d41833319e69a1
Hi, Johan!
You're absolutely right! Great catch! 🙌 💯
It took me a while to understand the tests tho 😅 But they do cover everything deeply! Maybe preceding your tests with some simpler example would help, e.g:
it.only('should subscribe twice', () => {
let count = 0;
const o = new Observable(observer => {
count++;
observer.complete();
});
const r = run(() => $(o));
r.subscribe();
r.subscribe();
expect(count).toBe(2); // it's 1 now!
})
Thank you!
Would you like to create a PR on this? 😊
Good idea about the extra test!
I'm not sure what happens in github when creating a pull request of a commit on top of commits that are already in a different pull request? So that's one reason why I didn't create one already... I'll see what I can do.
Yeah, the diff would be huge. I'm sure it'll wait. We have this issue so that we wont forget about this!
I added your suggestion as extra test and linked the commit to this issue.
For the PR I'll wait for #5 to complete first because this commit is dependent on it.
NB: that I use squash-merge, so you'll have to rebase interactively to drop commits from #5
Hello,
Thanks again for this amazing work!
I tried out it's behavior when the same observable returned from
run()
is subscribed multiple times. I expect it to then also subscribe the upstream observables multiple times. (It should not share the subscription I think. If that is desirable, one could always useshareReplay()
or something.) But currently that is not what's happening.I created some tests in this commit: 5da93e09779827dc1efb180e1ddd93a127830d6c. Most of them fail. I also tried to make a quick fix, but failed to do so yet...
Do you agree about the new tests I made? If not, what do you think should happen when multiple subscribers subscribe the same runner?
I hope you'll look into this as well.
Greetings, Johan