Open kpeeters opened 6 years ago
Expressions of the form 'tensor = components expression' should be valid substitution rules for evaluate, but they do not produce the right tree structure:
evaluate
{r,t}::Coordinate. {m,n}::Indices(values={t,r}, position=fixed). ex:= A_{m} = A_{m}; rl:= A_{t} = 3; evaluate(ex, rl, rhsonly=True, simplify=True) ex2:= A_{m}; evaluate(ex2, ex);
All examples avoid this by doing a substitute rather than an evaluate, but this should nevertheless be fixed.
substitute
Expressions of the form 'tensor = components expression' should be valid substitution rules for
evaluate
, but they do not produce the right tree structure:All examples avoid this by doing a
substitute
rather than anevaluate
, but this should nevertheless be fixed.