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kpu / kenlm

KenLM: Faster and Smaller Language Model Queries
http://kheafield.com/code/kenlm/
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model.full_socres #419

Open zidong-onepiece1 opened 1 year ago

zidong-onepiece1 commented 1 year ago

hi ken!

model = kenlm.Model("ngram.model")

def score_sentence(self, words_list):
        sentence = " ".join(words_list)
        score = 0
        error_count = 0
        for (prob, **length**, oov) in enumerate(model.full_scores(sentence)):
            ...

If length equals 1, or 2, or 3, what does it mean？

thanks!