Open DonGovi opened 6 years ago
In F.smoothL1loss, if "size_average" is True, loss / (samples_num * location_vector_length), you set "size_average" to False, but only devided by samples_num. Why is it?
In F.smoothL1loss, if "size_average" is True, loss / (samples_num * location_vector_length), you set "size_average" to False, but only devided by samples_num. Why is it?