Open Seanmatthews opened 1 year ago
No, there isn't anything about that. If we find a nice way to express it I can add this to the backlog.
Anyway I found a workaround that could work in some cases.... but is really far from to be an elegant solution and it doesn't work in general cases:
use std::collections::HashMap;
use rstest::*;
use rstest_reuse::{self, *};
#[derive(PartialEq, Eq, Debug, Hash)]
struct AStruct {
a: u32,
b: u32,
}
impl AStruct {
fn add(&self) -> u32 {
self.a + self.b
}
fn mul(&self) -> u32 {
self.a * self.b
}
}
#[template]
#[rstest]
#[case(AStruct{a: 1, b: 1})]
#[case(AStruct{a: 2, b: 3})]
fn base(#[case] s: AStruct) {}
#[fixture]
#[once]
fn add_expected() -> HashMap<AStruct, u32> {
let mut m = HashMap::new();
m.insert(AStruct { a: 1, b: 1 }, 2);
m.insert(AStruct { a: 2, b: 3 }, 5);
m
}
#[apply(base)]
fn test_add(#[case] s: AStruct, add_expected: &HashMap<AStruct, u32>) {
assert_eq!(s.add(), *add_expected.get(&s).unwrap());
}
#[fixture]
#[once]
fn mul_expected() -> HashMap<AStruct, u32> {
let mut m = HashMap::new();
m.insert(AStruct { a: 1, b: 1 }, 1);
m.insert(AStruct { a: 2, b: 3 }, 6);
m
}
#[apply(base)]
fn test_mul(#[case] s: AStruct, mul_expected: &HashMap<AStruct, u32>) {
assert_eq!(s.mul(), *mul_expected.get(&s).unwrap());
}
Say I have a struct for which a number of functions are implemented.
Now, I'd like to be able to create a template with a number of AStruct instantiations defined:
Everything is fine so far. However, now I'd like to test the different operations using the AStruct instantiations that I've already defined. Can I do this with templates? Or is there another mechanism by which I could achieve this?