Open dsldsl opened 4 days ago
The error message indicates that thread_id_value
and user_id_value
are not being passed correctly to the build_output
method. This could be due to how the method is being called or how the inputs are being handled in the UI.
To ensure that thread_id_value
and user_id_value
are required fields and are correctly passed to the build_output
method, you can add default values for the optional parameters and ensure that the required parameters are correctly passed. Here is the updated code snippet:
from typing import Optional
from langflow.custom import Component
from langflow.io import MessageTextInput, Output
from langflow.schema import Data
from bson import ObjectId
from steer.controllers.threadsync_controller import get_thread_by_id
class UpdateStateComponent(Component):
display_name = "UpdateStateComponent"
description = "Use as a template to create your own component."
documentation: str = "http://docs.langflow.org/components/custom"
icon = "custom_components"
inputs = [
MessageTextInput(name="thread_id_value", display_name="Thread ID"),
MessageTextInput(name="user_id_value", display_name="User ID"),
MessageTextInput(name="current_question", display_name="current_question"),
MessageTextInput(name="prompt_question", display_name="prompt_question"),
MessageTextInput(name="followup_depth", display_name="followup_depth"),
MessageTextInput(name="segue_depth", display_name="segue_depth"),
]
outputs = [
Output(display_name="Output", name="output", method="build_output"),
]
def build_output(self, thread_id_value: str, user_id_value: str, current_question: Optional[str] = None, prompt_question: Optional[str] = None,
followup_depth: Optional[str] = None, segue_depth: Optional[str] = None):
update_kwargs = {}
if current_question:
update_kwargs['current_question'] = current_question
if prompt_question:
update_kwargs['prompt_question'] = prompt_question
if followup_depth:
update_kwargs['followup_depth'] = followup_depth
if segue_depth:
update_kwargs['segue_depth'] = segue_depth
update_current_state(thread_id_value, user_id_value, update_kwargs)
Ensure that when you call the build_output
method, you are passing thread_id_value
and user_id_value
as arguments. If these values are being provided through a UI, make sure the UI is correctly sending these values to the method [1].
To continue talking to Dosu, mention @dosu.
@dosu the UI in langflow component has those fields filled in. (in the UI, i manually type the inputs) But i'm getting this error when i try to build / run. What could that be?
@dosu can you explain how the stop() function works with reguards to multiple outputs and this error:
To resolve the error "Error Building Component. Error building Component Flow State Router: You must specify an output name to call stop" and properly use the stop()
function with multiple outputs in your custom Langflow component, you need to ensure that you specify the output_name
parameter when calling the stop()
function if there are multiple outputs.
Here is the relevant part of the stop()
function from your CustomComponent
class:
def stop(self, output_name: str | None = None):
if not output_name and self.vertex and len(self.vertex.outputs) == 1:
output_name = self.vertex.outputs[0]["name"]
else:
raise ValueError("You must specify an output name to call stop")
if not self.vertex:
raise ValueError("Vertex is not set")
try:
self.graph.mark_branch(vertex_id=self.vertex.id, output_name=output_name, state="INACTIVE")
except Exception as e:
raise ValueError(f"Error stopping {self.display_name}: {e}")
To properly use the stop()
function, you need to call it with the output_name
parameter if your component has multiple outputs. Here is an example of how to call the stop()
function correctly:
# Assuming you have a CustomComponent instance named custom_component
# and you want to stop a specific output named "output1"
custom_component.stop(output_name="output1")
If your component has only one output, you can call the stop()
function without specifying the output_name
, and it will automatically use the single output name:
# Assuming you have a CustomComponent instance named custom_component
# and it has only one output
custom_component.stop()
For example, if you have a MultipleOutputsComponent
class defined as follows:
from langflow.custom import Component
from langflow.inputs import MessageTextInput, IntInput
from langflow.template import Output
class MultipleOutputsComponent(Component):
display_name = "Multiple Outputs Component"
description = "A component with multiple outputs."
icon = "icon-name"
inputs = [
MessageTextInput(display_name="Input", name="input"),
IntInput(display_name="Number", name="number"),
]
outputs = [
Output(display_name="Certain Output", name="certain_output", method="certain_output"),
Output(display_name="Other Output", name="other_output", method="other_output"),
]
def certain_output(self) -> str:
return f"This is my string input: {self.input}"
def other_output(self) -> int:
return f"This is my int input multiplied by 2: {self.number * 2}"
You would need to call the stop()
function with the appropriate output_name
:
# Assuming you have an instance of MultipleOutputsComponent named multiple_outputs_component
multiple_outputs_component.stop(output_name="certain_output")
By ensuring that you provide the output_name
when there are multiple outputs, you can avoid the error and properly use the stop()
function in your custom Langflow component [1][2][3].
To continue talking to Dosu, mention @dosu.
[closed]