Defining multiple SASS files do not result in multiple CSS files (as described in the documentation). All given SASS files are combined into one and they use the path and filename of the first JS file given. If no JS file has been used, a fallback name mix.css is used in the default folder.
Looks to me like the .sass()output parameter is never used and instead the first value from the .js()output parameter instead.
Description:
Defining multiple SASS files do not result in multiple CSS files (as described in the documentation). All given SASS files are combined into one and they use the path and filename of the first JS file given. If no JS file has been used, a fallback name
mix.css
is used in the default folder.Looks to me like the
.sass()
output
parameter is never used and instead the first value from the.js()
output
parameter instead.Steps To Reproduce:
And this is the output
when I comment out or change the order of the JS files, this happens:
Output
Third try, I remove the remaining JS file like this:
Output: