Hi, I am confused about some places in memeber test:
1、why use (-1, 1, 1, ...1) as the test vector
2、In extract, why only extract the first element b0 of b. It looks that the second row of ACC meets b(x) = a(x) * s(x) + e(x) + u*Y^v，if set X=0 and only extract constant then b0 = a(0)*s(0)+e(0)，the v is disappear and looks not an encryption about v
Do I mistake something and what's the principle behind the implement. It looks not consist with the paper.
Hi, I am confused about some places in memeber test: 1、why use (-1, 1, 1, ...1) as the test vector 2、In extract, why only extract the first element
b0ofb. It looks that the second row of ACC meetsb(x) = a(x) * s(x) + e(x) + u*Y^v，if set X=0 and only extract constant then b0 = a(0)*s(0)+e(0)，thevis disappear and looks not an encryption aboutvDo I mistake something and what's the principle behind the implement. It looks not consist with the paper.
Thanks