why multiplied by 64 after cv2.resize() in image.py??

[guoqiang01486]

hi,leeyeehoo,thank u for the released codes. In image.py, I don't understand the meaning of the code" target = cv2.resize(target,(target.shape[1]/8,target.shape[0]/8),interpolation = cv2.INTER_CUBIC)64 ",maybe the reason is the resize scale is 1/8,but 64 means the pixels64,it is irrelevant to the scale . or it only increases the values of pixels,if so ,why 64 not others. I just want to know why?

[ZhengPeng7]

hi,leeyeehoo,thank u for the released codes. In image.py, I don't understand the meaning of the code" target = cv2.resize(target,(target.shape[1]/8,target.shape[0]/8),interpolation = cv2.INTER_CUBIC)64 ",maybe the reason is the resize scale is 1/8,but _64 means the pixels_64,it is irrelevant to the scale . or it only increases the values of pixels,if so ,why 64 not others. I just want to know why?

Because 8 8 = 64. Actually, `resize + 64` should be a simplified method of the convolution that sums the 8x8 grid, which I did in my own implementation.

[hellowangqian]

@ZhengPeng7 The operation "resize and then *64" will change the count value (target.sum()) though not significantly.

[ZhengPeng7]

Certainly, that's why I called it the 'simplified one', and using convolution to do the count is the precise answer.

[elharroussomar]

its give errors why for me. can any one help.

target = cv2.resize(target,(target.shape[1]/8,target.shape[0]/8),interpolation = cv2.INTER_CUBIC)*64 TypeError: integer argument expected, got float

[Akbarkhan87]

its give errors why for me. can any one help.

target = cv2.resize(target,(target.shape[1]/8,target.shape[0]/8),interpolation = cv2.INTER_CUBIC)*64 TypeError: integer argument expected, got float

Just type target = cv2.resize(target,(target.shape[1]//8,target.shape[0]//8),interpolation = cv2.INTER_CUBIC)*64