In this case:
* // The output COBOL structure
01 A.
03 OCCURS-COUNTERS--C.
05 B--C PIC 9(9) COMP-5.
05 E--C PIC 9(9) COMP-5.
03 B OCCURS 0 TO 10 DEPENDING ON B--C.
05 C.
07 d OCCURS 10 PIC X(32) DISPLAY.
03 E OCCURS 0 TO 10 DEPENDING ON E--C.
05 f PIC X(32) DISPLAY.
E is indented relative to d instead of A.
Original issue reported on code.google.com by fady.mou...@gmail.com on 2 Apr 2012 at 9:18
Original issue reported on code.google.com by
fady.mou...@gmail.com
on 2 Apr 2012 at 9:18