Open grey4owl opened 2 years ago
You may have already figured out the solution, but it passes a copy of flags to the function. It is defined in the "init" function documentation, but I agree it doesn't tie it together into a coherent example.
const args = require("args");
args.option("port", "The port on which the app will be running.", 4040);
args.command("run", "Run dev version on localhost.", (name, sub, options) => {
console.log("Running on port: " + options.port);
}, ["r"]);
args.parse(process.argv);
Hi, Is it possible to create something like this:
So you can use it like:
mycli run --port 3333
and then output:Running on port: 3333
. In case you are not using a--port
flag, the output should be:Running on port: 4040
.I did not find anything similar in the documentation..