Closed MikeBagos closed 12 years ago
Consider the code:
@border-color: #B2B; .testme(@culprit: @border-color) { filter: progid:DXImageTransform.Microsoft.gradient(startColorstr='@{culprit}', endColorstr='@{culprit}'); // IE } .la { .testme(); } .la2 { .testme(#FF0000); } .la3 { .testme(#FF0110); }
This will wield:
.la { filter: progid:dximagetransform.microsoft.gradient(startColorstr='#bb22bb', endColorstr='#bb22bb'); } .la2 { filter: progid:dximagetransform.microsoft.gradient(startColorstr='#bb22bb', endColorstr='#bb22bb'); } .la3 { filter: progid:dximagetransform.microsoft.gradient(startColorstr='#bb22bb', endColorstr='#bb22bb'); }
Which is incorrect, because the color does not update!
duplicate of #534
Its actualy not string interpolation but use of the filter function... wrap the whole value in ~"" and I guess it will go away
Consider the code:
This will wield:
Which is incorrect, because the color does not update!