When testing the following code, I am able to compile and execute when using clang++.
#include <cppcoro/generator.hpp>
#include <cppcoro/recursive_generator.hpp>
#include <iostream>
#include <type_traits>
cppcoro::generator<int> numbers(int begin, int end)
{
for (int i = begin; i < end; ++i)
{
co_yield i;
}
}
int main(int argc, char* argv[])
{
int begin = 10;
int end = 30;
auto predicate = [](auto&& obj) -> bool { return true; };
auto filter = [&pred_ = predicate](auto&& val) -> cppcoro::generator<typename std::decay_t<decltype(val)>::iterator::value_type> {
for (auto&& _v : val) {
if (pred_(_v)) {
co_yield _v;
}
}
};
auto range = filter(numbers(begin, end));
for (auto i : range) {
std::cout << i << "\n";
}
}
However, g++ gives the following error:
clang-test.cpp: In instantiation of ‘main(int, char**)::<lambda(auto:12&&)> [with auto:12 = cppcoro::generator<int>; typename std::decay<decltype (val)>::type::iterator::value_type = int]’:
clang-test.cpp:26:44: required from here
clang-test.cpp:22:17: error: ‘co_yield’ cannot be used in a ‘constexpr’ function
22 | co_yield _v;
| ^~~~~~~~
Compilation with g++ succeeds if I remove the if statement in filter.
I am using gcc version 10.2.0 and clang version 10.0.1. I have not found an explanation for why this behavior would differ between platforms, but a solution under GCC would be appreciated.
When testing the following code, I am able to compile and execute when using clang++.
However, g++ gives the following error:
Compilation with g++ succeeds if I remove the if statement in filter.
I am using gcc version 10.2.0 and clang version 10.0.1. I have not found an explanation for why this behavior would differ between platforms, but a solution under GCC would be appreciated.