Closed li0604 closed 2 years ago
cut -f 1 name.list > id.list
use id instead
As @shenwei356 said, you need to provide a list of names. @
or 2:N:0:1
is not part of a name.
perl -ne 'print "$1\n" if /^@(\S+)/'
Thanks a lot. @lh3 @shenwei356
Hi everyone,
WHen I use the command “seqtk subseq in.fq name.lst > out.fq”, there is no anything in the out.fq. The details showed as following:
other command line works. So I don't what's the reason about this problem.
Would you mind sharing your experience?
Thanks a lot.