Closed phcoder closed 2 years ago
sizeof(&md5string[i * 2]) is a sizeof of a pointer, so 4 or 8 instead of intended 3 (2 hex digits + \0) leading to a potential overflow
sizeof(&md5string[i * 2]) is a sizeof of a pointer, so 4 or 8 instead of intended 3 (2 hex digits + \0) leading to a potential overflow