Closed GoogleCodeExporter closed 9 years ago
Response r = get("/x"); String y = r.path("x.y"); String z = r.path("x.z"); // Throws exception
Original issue reported on code.google.com by johan.ha...@gmail.com on 27 Nov 2013 at 12:30
johan.ha...@gmail.com
Original comment by johan.ha...@gmail.com on 27 Nov 2013 at 1:45
Original issue reported on code.google.com by
johan.ha...@gmail.com
on 27 Nov 2013 at 12:30