Closed dduugg closed 5 years ago
This fixes an issue where comparable?(x, y) != comparable?(y, x), when x is an instance of a subclass of Hash (or Array), and y is an instance of Hash (or Array) directly.
comparable?(x, y)
comparable?(y, x)
Hash
Array
Resolves https://github.com/liufengyun/hashdiff/issues/54
Thanks a lot @dduugg 👍
This fixes an issue where
comparable?(x, y)
!=comparable?(y, x)
, when x is an instance of a subclass ofHash
(orArray
), and y is an instance ofHash
(orArray
) directly.Resolves https://github.com/liufengyun/hashdiff/issues/54