Closed heiemooa closed 3 years ago
Hi, has this problem been solved? My version is 6.10.1, it seems that this problem still exists. old issue
"(a)=(acb)"
%28a%29=%28acb%29
sorry, I seem to be wrong,it need "format: "RFC1738"
Hi, has this problem been solved? My version is 6.10.1, it seems that this problem still exists. old issue
Expected Result
"(a)=(acb)"
Current Result
%28a%29=%28acb%29
version:6.10.1