#exec quoted

[denisdemaisbr]

hi all. is possible make a result of #exec quoted + terminate statement line ?

--- input --- int main(void) { const char uuid = #exec uuid const char date = #exec date -R return 0; }

--- output --- int main(void) { const char uuid = "a9403e0f-6717-481d-9971-2f41cdfd0a88"; const char date = "Sun, 11 Dec 2022 14:40:16 -0300"; return 0; }

$uuidgen a9403e0f-6717-481d-9971-2f41cdfd0a88

$date -R Sun, 11 Dec 2022 14:40:16 -0300

[logological]

I don't think you can change the behaviour of #exec itself, but you could always wrap it in another macro:

#define aexec(x) "#exec x
#define myexec(x) aexec(x)"

int main(void) {
  const char *date = myexec(date -R);
  return 0;
}

This would result in:

$ gpp -x test.c

int main(void) {
  const char *date = "Wed, 14 Dec 2022 10:35:03 +0100
";
  return 0;
}

Note that a newline appears within the quotes because date itself prints a newline. I suspect that there is no way of stripping the newline using GPP (meta)macros; you might need to do this by rewriting the command line to be executed. For example:

  const char *date = myexec(date -R | tr -d '\\\n');