Closed 5outh closed 6 years ago
This is best explained with an example. Take the following haskell program:
data F = F Int Int foo = \(_ `F` _) -> ()
Running brittany on this file produces the following, broken code:
brittany
data F = F Int Int foo = \(_F_) -> ()
This doesn't seem to happen outside of lambda arguments.
Brittany version:
brittany version 0.9.0.0 Copyright (C) 2016-2017 Lennart Spitzner There is NO WARRANTY, to the extent permitted by law.
I'm now realizing I'm a bit behind; will update presently to determine if this issue has been ironed out!
Updated to 0.11.0.0 and everything works as expected. Sorry for the noise!
This is best explained with an example. Take the following haskell program:
Running
brittany
on this file produces the following, broken code:This doesn't seem to happen outside of lambda arguments.
Brittany version:
I'm now realizing I'm a bit behind; will update presently to determine if this issue has been ironed out!