If I want to use $\psi\pm$ rather than $\langle \psi \rangle\pm$, then I need to consider conjugations for Equations 17 and 19, instead of Equation 16. C and T conjugations carry an extra change in helicity ($p_0 \mapsto \bar{p_0}$), so it's incorrect to say that Equations 17 and 19 have charge and time conjugations. They simply do not exist.
On the other hand, what ultimately matters is how observables change. While $p_0$ maps to $\bar p_0$, $J = \psi p_0 \widetilde \psi$ simply maps to $-J$, the helicity of which is unchanged. This would suggest that this works out fine.
If I want to use $\psi\pm$ rather than $\langle \psi \rangle\pm$, then I need to consider conjugations for Equations 17 and 19, instead of Equation 16. C and T conjugations carry an extra change in helicity ($p_0 \mapsto \bar{p_0}$), so it's incorrect to say that Equations 17 and 19 have charge and time conjugations. They simply do not exist.
On the other hand, what ultimately matters is how observables change. While $p_0$ maps to $\bar p_0$, $J = \psi p_0 \widetilde \psi$ simply maps to $-J$, the helicity of which is unchanged. This would suggest that this works out fine.