Closed wsttiger closed 10 years ago
Could it be that we need to implement the spin-orbit coupling contribution to the potential?
There are non-zero "k" coefficients to many of these elements. However to implement LS-coupling, it looks like (naively) unless something cancels, that we will have to use a complex version of MolDFT.
Indeed, assuming a "z" spin orientation, i.e. \sigma_3 aligns in the z-direction, we have to compute a contribution to the potential that looks like:
[ (Lz) (Lx + i Ly) ] [ (Lx - i Ly) (-Lz) ]
Sorry, I'm an idiot --- we don't have to use a z-orientation for spin. We should just be able to diagonalize the L-S matrix to make things simpler ... I'm just speculating now.
I think we need to implement it at some point, but I'm not sure this is the only problem - I tried setting the k components to zero in BigDFT to make a fairer comparison with MADNESS and for all the cases I tried the difference between zero and non-zero k components was negligible. I don't remember exactly which elements I tested but I tried quite a few and I'm pretty sure I did at least one or two of the heavier elements.
Another note is that I am using Rlm's instead of Ylm's, and if I can remember correctly, the math showed that in this case since we are doing a sum over "m", they should be equivalent, but this is one thing to check.
I just tried Kr setting k to zero and as suspected not much difference. I added the eigenvalues to your spreadsheet and I think the difference between what I got and what you got is probably due to different inputs to BigDFT rather than the lack of spin-orbit correction.
Fixed, and checked in.
Gives erroneous results with many 4th row elements in the periodic table -- Ge, Se, Kr, transition metals -- although Ca works and Sr (5th row element) gives decent results.