Closed smangul1 closed 7 years ago
Let's make this output per chain
CLLKLSILSNCVLKWYLKQVVLKGLLF 1 CCSAVRVIPFVLHQPLCLPCLKLLQFLLRQLFQCF 2
where CDD3 and number of reads supporting it
How do you think we need to deal wth partial overlapping reads? Count them? In case CDR3 was assembled from 2 partially-mapped reads, should count be 2?
Could you please explain your comment in more details? I do not understand it.
Made count be 2 (as sum of counts for partially overlapping reads).
Let's make this output per chain
CLLKLSILSNCVLKWYLKQVVLKGLLF 1 CCSAVRVIPFVLHQPLCLPCLKLLQFLLRQLFQCF 2
where CDD3 and number of reads supporting it
How do you think we need to deal wth partial overlapping reads? Count them? In case CDR3 was assembled from 2 partially-mapped reads, should count be 2?