This is the only implementation of BASIC that use SQRT for square root instead of SQR?

marcIhm / yabasic

Yabasic - A simple Basic interpreter for Unix and Windows

http://www.yabasic.de

MIT License

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This is the only implementation of BASIC that use SQRT for square root instead of SQR? #52

Closed ghost closed 2 years ago

ghost commented 2 years ago

I have no idea why my code doesn't work as expected until I guessed what if the square root function is SQRT like on C family languages and it turned out I was right. Why did you choose SQRT instead of SQR from the beginning?

marcIhm commented 2 years ago

Hi, this decision is more than 25 years old; can't tell now ...

marcIhm commented 2 years ago

And: Sorry for the inconvenience, but this is something I cannot change now without affecting quite a lot of existing users ...