Closed roboton closed 2 years ago
Handling of empty tibble inconsistent with tidyr::unnest
> tidytable::unnest.(tibble::tibble(foo = list()), foo) Error in .l[[1]] : subscript out of bounds > tidyr::unnest(tibble::tibble(foo = list()), foo) # A tibble: 0 × 1 # … with 1 variable: foo <???>
Handling of empty tibble inconsistent with tidyr::unnest