Open bastianhjaeger opened 6 years ago
How do I add a interrupt to GPIO 0
This seems not to work (derived from user_basic/user_main.c):
#include "user_interface.h" #include "mqtt/mqtt_server.h" #include "user_config.h" #include "easygpio.h" static void sonoffBtnInterrupt(void* arg) { uint8_t value = easygpio_inputGet(13); easygpio_outputSet(13, !value); } int interruptOne = 42; void ICACHE_FLASH_ATTR user_init() { struct station_config stationConf; // Initialize the UART uart_div_modify(0, UART_CLK_FREQ / 115200); os_printf("\r\n\r\nMQTT Broker starting\r\n"); // Setup STA ... // Allow larger number of TCP (=MQTT) clients ... easygpio_pinMode(13, EASYGPIO_PULLUP, EASYGPIO_OUTPUT); easygpio_outputSet(13, 0); // turn on //easygpio_pinMode(0, EASYGPIO_PULLUP, EASYGPIO_INPUT); easygpio_attachInterrupt(0, EASYGPIO_PULLUP, &sonoffBtnInterrupt, &interruptOne); //Start MQTT broker MQTT_server_start(MQTT_PORT, MQTT_MAX_SUBSCRIPTIONS, MQTT_MAX_RETAINED_TOPICS); }
Using the scripting language is no option?
No. I tried backtracking from the script method, but unfortunately do not see the issue.
Any idea?
How do I add a interrupt to GPIO 0
This seems not to work (derived from user_basic/user_main.c):