+Unlike many other examples, such as the dpcos in the Scott model of PCF, or
+Scott's D∞, the dpco of ordinals, while algebraic, does not have a small
+(compact) basis. If it did, we could take the join of all the basis elements to
+obtain a greatest ordinal, which does not exist.
Maybe I'm missing something, but presumably the booleans form a small basis, just like for the type of all (small) propositions?
On Mon, 3 Jun 2024, 16:05 Ulrik Buchholtz, @.***> wrote: