Open masak opened 2 years ago
Just noticed that this test doesn't test the right thing.
{ my $program = q:to/./; func infix:<n>(left, right) { return 20; } say(4 * 5); . outputs $program, "20\n", "using an operator after defining it works"; }
It's not using the defined n operator, it's using the built-in *, which is quite uninteresting.
n
*
Just noticed that this test doesn't test the right thing.
It's not using the defined
n
operator, it's using the built-in*
, which is quite uninteresting.