Closed mattbierner closed 10 years ago
the syntax
let x = 1, y = 3 in x + y;
should be functionally equivalent to
let x = 1 in let y = 3 in x + y;
The case:
let x = 3, x = 1 in x;
is currently invalid because x is bound twice. But
let x = 3 in let x = 1 in x;
is valid.
This is related to #60.
related to #62
the syntax
should be functionally equivalent to
The case:
is currently invalid because x is bound twice. But
is valid.
This is related to #60.