How to get currently scraped URL ?

[DannyCork]

may appear crude but why not set the url as a variable and then output it? See code below

var Xray = require('x-ray');  
var x = Xray();    
var url = 'http://www.wirdgroup.com' ;

x(url, 'title')(function(err, result) {
    console.log ('Connecting to ' + url);
    console.log('error is ' + err);
    console.log('result is ' + result);
})

[simonseddon]

I think the OP means the currently followed URL, i.e. from a found & followed link inside an x() instance