Closed MaximilianJHuber closed 6 years ago
Yeah, that was a quick shot. Indeed, your pA
is 1/gA
and hence pAx/pA = - gAx/gA
, so there is no typo, the second issue remains, though.
Ok. What is the second issue?
A.16 in the appendix: is your mcA
the paper's n^A
. If yes, I cannot match second line in A.16 with your definition of mcA
.
Good catch. I think it is a typo in the Garleanu Panageas appendix. Can you try to rederive A.16 from A.14 and tell me whether you obtain their formula vs my formula?
You are right. I collected all terms with a κ
from A.14 and found your expression, not the one in the paper.
How did you know it was a mistake? Again, is there a supporting document you have for your example?
Cool, thanks. I’ll upload some notes.
Actually just have a look at slides 9 here
I am working through your GarleanuPanageasModel and I think I found a typo, but I cannot be sure, because I do not know with certainty how your
pA
andmcA
maps into the paper'sg^A
andn^A
. The former is suggested by the definition ofκ
, the latter by the definition ofr
.Anyway, the denominator of equation 9 has the terms concerning
A
with a plus sign and the terms withB
with a minus sign. This is an error, unlesspAx/pA = - gAx/gA
.Furthermore, equation A.16 in the appendix defines
n^A
which resembles yourmcA
almost perfectly. But, the coefficient in the second line agrees with you definition ofmcA
, only ifγA/(1-γA) = 1
, which is not true.Is there a documentation that could accompany the example?