Currently, if a predicate is just a number, e.g. "a[3]", the expression is
evaluated against every node in the node-set, even though (in this example)
we can just pick the 3rd node.
We can make this a special case to improve efficiency
Original issue reported on code.google.com by peterj...@gmail.com on 3 Dec 2007 at 1:19
Original issue reported on code.google.com by
peterj...@gmail.com
on 3 Dec 2007 at 1:19