mclements
commented
6 years ago Alessandro,
Does this work with the version on GitHub? I need to push a new version to CRAN...
-- Mark
On 05/29/2018 01:41 PM, Alessandro Gasparini wrote:
Hello! I was replicating one of the examples from the vignette on predictnl that you sent me, and I couldn't reproduce the example with the linear regression model:
library(rstpm2)
> Loading required package: survival
> Loading required package: splines
>
> Attaching package: 'rstpm2'
> The following object is masked from 'package:survival':
>
> colon
set.seed(123456) x1 <- rnorm(1000) y <- rnorm(1000, x1) fit <- lm(y ~ x1) invert <- function(object, newdata) { thetahat <- coef(object) (newdata$y - thetahat[1])/thetahat[2] } predictnl(fit, invert, newdata = data.frame(y = seq(0, 2, by = 0.5)))
> Error in UseMethod("predictnl"): no applicable method for 'predictnl' applied
> to an object of class "lm"
I was expecting the predictnl.default method to be dispatched by default, but that did not happen. However, if I call it directly (and via the ::: operator - is it not exported on purpose?) if works fine:
rstpm2:::predictnl.default(fit, invert, newdata = data.frame(y = seq(0, 2, by = 0.5)))
> Estimate SE
> 1 0.007973223 0.03208338
> 2 0.505825537 0.03585955
> 3 1.003677852 0.04540490
> 4 1.501530166 0.05793476
> 5 1.999382481 0.07190551
Should this be useful, my R session info follows:
devtools::session_info()
> Session info -------------------------------------------------------------
> setting value
> version R version 3.5.0 (2018-04-23)
> system x86_64, mingw32
> ui RTerm
> language (EN)
> collate English_United Kingdom.1252
> tz Europe/London
> date 2018-05-29
> Packages -----------------------------------------------------------------
> package * version date source
> backports 1.1.2 2017-12-13 CRAN (R 3.5.0)
> base * 3.5.0 2018-04-23 local
> bbmle 1.0.20 2017-10-30 CRAN (R 3.5.0)
> compiler 3.5.0 2018-04-23 local
> datasets * 3.5.0 2018-04-23 local
> devtools 1.13.5 2018-02-18 CRAN (R 3.5.0)
> digest 0.6.15 2018-01-28 CRAN (R 3.5.0)
> evaluate 0.10.1 2017-06-24 CRAN (R 3.5.0)
> formatR 1.5 2017-04-25 CRAN (R 3.5.0)
> graphics * 3.5.0 2018-04-23 local
> grDevices * 3.5.0 2018-04-23 local
> grid 3.5.0 2018-04-23 local
> htmltools 0.3.6 2017-04-28 CRAN (R 3.5.0)
> knitr 1.20 2018-02-20 CRAN (R 3.5.0)
> lattice 0.20-35 2017-03-25 CRAN (R 3.5.0)
> magrittr 1.5 2014-11-22 CRAN (R 3.5.0)
> Matrix 1.2-14 2018-04-13 CRAN (R 3.5.0)
> memoise 1.1.0 2017-04-21 CRAN (R 3.5.0)
> methods * 3.5.0 2018-04-23 local
> mgcv 1.8-23 2018-01-21 CRAN (R 3.5.0)
> nlme 3.1-137 2018-04-07 CRAN (R 3.5.0)
> numDeriv 2016.8-1 2016-08-27 CRAN (R 3.5.0)
> Rcpp 0.12.17 2018-05-18 CRAN (R 3.5.0)
> rmarkdown 1.9 2018-03-01 CRAN (R 3.5.0)
> rprojroot 1.3-2 2018-01-03 CRAN (R 3.5.0)
> rstpm2 * 1.4.1 2017-09-20 CRAN (R 3.5.0)
> splines * 3.5.0 2018-04-23 local
> stats * 3.5.0 2018-04-23 local
> stats4 3.5.0 2018-04-23 local
> stringi 1.2.2 2018-05-02 CRAN (R 3.5.0)
> stringr 1.3.1 2018-05-10 CRAN (R 3.5.0)
> survival * 2.42-3 2018-04-16 CRAN (R 3.5.0)
> tools 3.5.0 2018-04-23 local
> utils * 3.5.0 2018-04-23 local
> withr 2.1.2 2018-03-15 CRAN (R 3.5.0)
> yaml 2.1.19 2018-05-01 CRAN (R 3.5.0)
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ellessenne
Hello! I was replicating one of the examples from the vignette on
predictnlthat you sent me, and I couldn't reproduce the example with the linear regression model:I was expecting the
predictnl.defaultmethod to be dispatched by default, but that did not happen. However, if I call it directly (and via the:::operator - is it not exported on purpose?) if works fine:Should this be useful, my R session info follows: