If a class C has a method named M, and its [metaclass or any of its base
classes] BM has both the
same name as C and a method named M, then calls to C.M may go to the wrong
implementation.
This is just silly.
Original issue reported on code.google.com by fwere...@gmail.com on 20 Jan 2009 at 8:35
Original issue reported on code.google.com by
fwere...@gmail.com
on 20 Jan 2009 at 8:35