Is there a way to make a struct with alternative namespace?

[RinChanNOWWW]

For example

#[derive(Debug, YaDeserialize, YaSerialize, Default)]
#[yaserde(namespace = "{namespace}")]
pub struct MyStruct {
   // ...
}

I want to the {namespace} be alternative.

Or, can I not specify #[yaserde(namespace = "{namespace}")] if the XML has a namespace?

If I don't specify namespace, it will return Error: bad namespace for xxx, found xxxx

[RinChanNOWWW]

PTAL @MarcAntoine-Arnaud

[MarcAntoine-Arnaud]

Hello, Sorry for the delay. For namespace, the derive cannot take variable. Some example are provided in the repo, like https://github.com/media-io/yaserde/blob/master/examples/src/bbigras_namespace.rs 2 attributes are important :

• Namespace to declare prefix with the URL, as the xmlns does. You can declare many on a struct.
• prefix to use the namespace (it can be on the struct or a field), it requires to matches to the prefix defined in attribute namespace.

Is it clear ?

Best regards

[RinChanNOWWW]

Thanks for answering.

What is the best way to deal with the case if the namespace could change? Make two different structs? Is there a simpler way?

[MarcAntoine-Arnaud]

Yes it's the simplest. And using flatten is great to do:

#[derive(YaDeserialize)]
#[yaserde ...]
struct MyNamespace1 {
  #[yaserde(flatten)]
  fields: Fields
}

#[derive(YaDeserialize)]
#[yaserde ...]
struct MyNamespace2 {
  #[yaserde(flatten)]
  fields: Fields
}

#[derive(YaDeserialize)]
struct Fields {
  ...
}

Like that you didn't re-wrote fields.

[RinChanNOWWW]

Thanks.