Closed GoogleCodeExporter closed 8 years ago
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好象CoreThread.cpp中AttachPalToList方法缺少一个判断:
void CoreThread::AttachPalToList(PalInfo *pal)
{
GroupInfo *grpinf;
//add start
if(!pal){
printf("Attach a NULL Pal !\n");
return;
}
//add end
Original comment by kingbo.l...@gmail.com
on 6 Nov 2009 at 5:52
另外我还是喜欢启动时进入群显示方式:
MainWindow.cpp中737行:
model = GTK_TREE_MODEL(g_datalist_get_data(&mdlset, "regular-paltree-model"));
改为了
model = GTK_TREE_MODEL(g_datalist_get_data(&mdlset, "group-paltree-model"));
Original comment by kingbo.l...@gmail.com
on 6 Nov 2009 at 5:55
每次都是第二个创建的线程在一定时间内异常死掉退出,在��
�创建第二个线程的位置。
Original comment by kingbo.l...@gmail.com
on 6 Nov 2009 at 7:00
继续加清空判断:
CoreThread.cpp中:
GroupInfo *CoreThread::GetPalRegularItem(PalInfo *pal)
{
GSList *tlist;
//add start
if(!pal)return NULL;
//add end
GroupInfo *CoreThread::GetPalSegmentItem(PalInfo *pal)
{
GSList *tlist;
char *name;
GQuark grpid;
//add start
if(!pal)return NULL;
//add end
GroupInfo *CoreThread::GetPalGroupItem(PalInfo *pal)
{
GSList *tlist;
GQuark grpid;
//add start
if(!pal)return NULL;
//add end
MainWindow.cppk中:
bool MainWindow::GroupGetPaltreeItem(GtkTreeModel *model, GtkTreeIter *iter,
GroupInfo *grpinf)
{
GroupInfo *pgrpinf;
//add start
if(!grpinf)return false;
//add end
好象就这些了,基本上加上对GroupInfo指针判断,一下午没出��
�题了
Original comment by kingbo.l...@gmail.com
on 6 Nov 2009 at 9:43
郁闷,最近几天都在学校外面找工作,估计我自己是没机会修�
��这个错误了.
我已经把你加入项目成员了,你先把这个问题解决一下吧,谢�
��!
Original comment by jal...@163.com
on 6 Nov 2009 at 12:08
google这动作模式我还不会,不知道怎么去做
Original comment by kingbo.l...@gmail.com
on 6 Nov 2009 at 12:17
晕,看了半天svn,最后看好象是权限问题,提交不上去
svn commit CoreThread.cpp MainWindow.cpp
日志信息未修改,或未指定
a)终止,c)继续,e)编辑:
c
认证领域: <http://iptux.googlecode.com:80> Google Code Subversion Repository
“kingbo”的密码:
认证领域: <http://iptux.googlecode.com:80> Google Code Subversion Repository
用户名: kingbo@126.com
“kingbo@126.com”的密码:
认证领域: <http://iptux.googlecode.com:80> Google Code Subversion Repository
用户名: kingbo@126.com
“kingbo@126.com”的密码:
svn: 提交失败(细节如下):
svn: 方法 MKACTIVITY 失败于
“/svn/!svn/act/07b6b6ef-e1fa-4836-85df-71c46b26da1a”: 认
证失败: 不能认证到服务器: 被拒绝的 Basic 挑战
(http://iptux.googlecode.com)
Original comment by kingbo.l...@gmail.com
on 6 Nov 2009 at 3:54
commiter要按https重新co一次,才能有权限修改的
Original comment by Pentie
on 8 Nov 2009 at 6:18
Original comment by jal...@163.com
on 20 Nov 2009 at 10:08
Original issue reported on code.google.com by
kingbo.l...@gmail.com
on 5 Nov 2009 at 7:28