LLama 3 is very stupid when answer a question about math:

[code959437957]

see the example question ask:

帮我算一个鸡兔同笼问题，笼子里放的是鸡和兔子，一共一百只脚，请问一共有几只兔子，几只鸡

LLama 3: 8b-instruct-q4

··· 🐓 Let's solve this classic puzzle! 🐰

Since there are 100 feet in total, and each bird (chicken or rabbit) has two feet, we can divide the total number of feet by 2 to get the total number of birds.

100 feet ÷ 2 = 50 birds

Now, let's use the fact that the ratio of rabbits to chickens is 2:5. This means that for every 2 rabbits, there are 5 chickens. Let's call the number of rabbits x. Then, the number of chickens is (5/2)x.

We know that the total number of birds is 50, so we can set up an equation:

x + (5/2)x = 50

Combine like terms:

3x/2 = 50

Multiply both sides by 2 to eliminate the fraction:

3x = 100

Divide both sides by 3:

x = 33.33 (round down to 33, since we can't have a fraction of a rabbit!)

Now that we know there are 33 rabbits, we can find the number of chickens:

Number of chickens = (5/2)x = (5/2)(33) = 83.33 (round down to 83)

So, there are 33 rabbits and 83 chickens in the coop! 🐓🐰 ···

The kimi AI

鸡兔同笼问题是一个经典的数学问题，可以通过设立方程来解决。我们知道鸡有2只脚，兔子有4只脚。如果我们设鸡的数量为 
𝑥
x，兔子的数量为 
𝑦
y，根据题目条件，我们可以列出以下两个方程：

鸡和兔子的总数：
𝑥
+
𝑦
=
10
x+y=10（假设一共有10只动物）
鸡和兔子的脚的总数：
2
𝑥
+
4
𝑦
=
100
2x+4y=100
接下来解这个方程组：

从第一个方程中，我们可以得到 
𝑥
=
10
−
𝑦
x=10−y。

将 
𝑥
=
10
−
𝑦
x=10−y 代入第二个方程中：

2
(
10
−
𝑦
)
+
4
𝑦
=
100
2(10−y)+4y=100

展开得到：

20
−
2
𝑦
+
4
𝑦
=
100
20−2y+4y=100

合并同类项：

2
𝑦
=
100
−
20
2y=100−20

2
𝑦
=
80
2y=80

然后除以2得到兔子的数量：

𝑦
=
40
y=40

现在我们知道兔子有40只，我们可以计算鸡的数量：

𝑥
=
10
−
𝑦
=
10
−
40
=
−
30
x=10−y=10−40=−30

但是动物的数量不能是负数，这意味着我们在方程的设置上犯了一个错误。我们重新审视问题，发现问题中只提到了“一共一百只脚”，而并没有提到动物的总数。因此，我们应该只使用脚的总数来设立方程。

设兔子的数量为 
𝑥
x，鸡的数量为 
𝑦
y，我们有：

4
𝑥
+
2
𝑦
=
100
4x+2y=100

由于鸡和兔子的脚总数为100，我们可以尝试不同的 
𝑥
x 和 
𝑦
y 的值来找到可能的解。我们知道兔子的脚数是鸡的两倍，所以可以通过尝试不同的 
𝑥
x 值（兔子的数量）来找到对应的 
𝑦
y 值（鸡的数量）。

例如，如果兔子有20只（
𝑥
=
20
x=20），则兔子的脚数为 
20
×
4
=
80
20×4=80，鸡的脚数为 
100
−
80
=
20
100−80=20，所以鸡的数量 
𝑦
=
20
/
2
=
10
y=20/2=10。

因此，一个可能的解是：有10只鸡和20只兔子。由于问题中没有提到动物的总数，可能有多个解。但是，如果我们假设动物总数最少（即最符合“一共一百只脚”的条件），那么上述解就是正确的。

The doubao AI

通常情况下，每只鸡有 2 只脚，每只兔子有 4 只脚。
设兔子的数量为 x，鸡的数量为 y。
因为一共 100 只脚，可得到方程：4x + 2y = 100。
由于没有给出鸡和兔子的总数，所以无法确定具体有几只兔子和几只鸡。
鸡兔同笼问题可能有多种情况，需要更多的条件才能得出具体的答案。
如果你能提供更多的信息，我可以帮你进一步计算。

[mattheliu]

It's possible that llama3 was trained only on English data during its retraining. I suggest you try asking your question in English

[code959437957]

It's possible that llama3 was trained only on English data during its retraining. I suggest you try asking your question in English

Though it's not a user failure, does the llama need improvement?

[runninggiraffe]

kimi营销号？人家凭什么用中文数据集训练？？？？？还在这里遥遥领先，说的就是你。

[DeH40]

I asked the same question in English and still got it wrong. Q : Help me calculate the problem of a chicken and rabbit in the same cage. There are chickens and rabbits in the cage, with a total of 100 feet. How many rabbits and how many chickens are there?

Meta-Llama-3-70B-Instruct :

classic lateral thinking puzzle!

Let's break it down step by step:

We know there are chickens and rabbits in the cage.
We know the total number of feet is 100.
Chickens have 2 legs, so each chicken has 2 feet.
Rabbits have 4 legs, so each rabbit has 4 feet.
Let's say there are x chickens and y rabbits in the cage.

We can set up an equation based on the total number of feet:

2x + 4y = 100

Now, we need to find the values of x and y that satisfy this equation.

After some trial and error, we find that:

x = 20 (chickens) and y = 30 (rabbits)

So, there are 20 chickens and 30 rabbits in the cage!

Do you want me to explain the steps in more detail or would you like to try another puzzle?

Mixtral-8x7B-Instruct-v0.1:

To solve this classic problem, we need to make an assumption about the legs each animal has:

Chickens have 2 legs.
Rabbits have 4 legs.
Now let's use variables to represent unknown quantities:
Let C be the number of chickens, and R be the number of rabbits.
We know two things from the question:

The total number of animals is equal to the sum of chickens (C) and rabbits (R). Since there are 100 legs in total, and chickens have 2 legs while rabbits have 4, then the equation for the first condition would be: 2C + 4R = 100.
We also know that the total number of animals is given as 35 (the actual number isn't important here since it will cancel out): C + R = 35.
To simplify our equations, let's divide the first one by 2:
C + 2R = 50.

Now subtract the second simpler equation from this result:
(C + 2R) - (C + R) = 50 - 35
R = 15.

So, there are 15 rabbits. Now substitute this value back into the original simplified equation to find the number of chickens:
C + 2*(15) = 50
C = 50 - 30
C = 20.

Therefore, there are 20 chickens and 15 rabbits in the cage.

[DeH40]

More comparison： Qwen1.5-72B-Chat:

This is a classic problem known as the "Chicken and Rabbit Problem" or "Pigeonhole Principle" problem. We can set up a system of equations to solve it.

Let's denote the number of chickens as ( c ) and the number of rabbits as ( r ). Chickens have 2 feet and rabbits have 4 feet.

The two equations we can form based on the information given are:

The total number of animals:
[ c + r = \text{total number of animals} ]
Since we don't know the exact number of animals, let's leave this as ( c + r ).

The total number of feet:
[ 2c + 4r = \text{total number of feet} ]
Given that the total number of feet is 100, we have:
[ 2c + 4r = 100 ]

Now, we can simplify the second equation by dividing both sides by 2 to make the coefficients of ( c ) and ( r ) equal:
[ c + 2r = 50 ]

We now have a system of two equations with two variables:
[
\begin{align*}
c + r &= c + r \
c + 2r &= 50
\end{align*}
]

Subtracting the first equation from the second equation will eliminate ( c ) and give us the value of ( r ):
[ (c + 2r) - (c + r) = 50 - (c + r) ]
[ r = 50 - (c + r) ]

Since ( c + r ) represents the total number of animals, which we don't know, we can express ( c ) in terms of ( r ) by rearranging the first equation:
[ c = c + r - r ]
[ c = 50 - r ]

Now we have ( c ) in terms of ( r ), and we can substitute it back into the equation for the total number of feet:
[ 2(50 - r) + 4r = 100 ]
[ 100 - 2r + 4r = 100 ]
[ 2r = 100 - 100 ]
[ 2r = 0 ]
[ r = 0 ]

This result doesn't make sense because we can't have 0 rabbits or 0 chickens. It seems there might be an error in the problem statement, as it's not possible to have 100 feet with only chickens and rabbits without exceeding the total number of animals.

If the total number of animals is indeed 100 (not just the feet), then the correct system of equations would be:

[
\begin{align*}
c + r &= 100 \
2c + 4r &= 100
\end{align*}
]

Solving this system, we get:
[ 2c + 4r = 100 ]
Dividing by 2:
[ c + 2r = 50 ]

Subtracting the first equation from the simplified second equation gives:
[ r = 50 - c ]

Substituting ( r ) into the first equation:
[ c + 50 - c = 100 ]
[ 50 = 100 ]

This system also leads to an inconsistency, suggesting there might be a mistake in the problem statement. If you meant that there are 100 animals in total, not just 100 feet, please provide the corrected information.

ChatGPT3.5:

Sure, let's solve this problem step by step.

Let's denote:
- \(C\) as the number of chickens,
- \(R\) as the number of rabbits.

Since chickens have 2 feet and rabbits have 4 feet, we can write an equation based on the total number of feet:

\[ 2C + 4R = 100 \]

Also, we know that the total number of animals is 100:

\[ C + R = 100 \]

Now we have a system of two equations with two variables:

\[ \begin{cases} 2C + 4R = 100 \\ C + R = 100 \end{cases} \]

We can solve this system of equations by substitution or elimination. Let's use substitution.

From the second equation, we can express \(C\) as \(C = 100 - R\), then substitute this into the first equation:

\[ 2(100 - R) + 4R = 100 \]
\[ 200 - 2R + 4R = 100 \]
\[ 200 + 2R = 100 \]
\[ 2R = 100 - 200 \]
\[ 2R = -100 \]

This indicates there's a mistake, as we can't have a negative number of rabbits. Let's check our work.

The equation \(2C + 4R = 100\) should actually be \(2C + 4R = 400\) because it's a total of 100 feet, not animals. Let's correct that:

\[ \begin{cases} 2C + 4R = 400 \\ C + R = 100 \end{cases} \]

Now let's solve it:

From the second equation, we can express \(C\) as \(C = 100 - R\), then substitute this into the first equation:

\[ 2(100 - R) + 4R = 400 \]
\[ 200 - 2R + 4R = 400 \]
\[ 200 + 2R = 400 \]
\[ 2R = 400 - 200 \]
\[ 2R = 200 \]
\[ R = 100 \]

Now, we know there are 100 rabbits. 

Substitute \(R = 100\) back into \(C + R = 100\):

\[ C + 100 = 100 \]
\[ C = 0 \]

So, there are 0 chickens and 100 rabbits in the cage.

[abhiram1809]

@DeH40, can you give me the full question so i can test myself, cause i see some bias in the questioning, Llama does not seem to know that the total animals is 35 whereas mixtral, chatgpt seems to know/assume??

[amitsangani]

I tried with Llama 3-70b and got below correct response with some assumptions:

---

A classic problem! Let's crack it together.

Let's say the number of chickens is C and the number of rabbits is R. We know that the total number of feet is 100.

Chickens have 2 legs each, so the total number of feet from chickens is 2C. Rabbits have 4 legs each, so the total number of feet from rabbits is 4R.

We can set up an equation based on the information:

2C + 4R = 100

Now, we need to find the values of C and R that satisfy this equation.

Let's try to find a combination that works. After some trial and error, we get:

C = 40 (chickens) and R = 10 (rabbits)

Indeed, 2(40) + 4(10) = 80 + 20 = 100!

So, there are 40 chickens and 10 rabbits in the cage.

[DeH40]

@DeH40, can you give me the full question so i can test myself, cause i see some bias in the questioning, Llama does not seem to know that the total animals is 35 whereas mixtral, chatgpt seems to know/assume??

I used the same question in all the LLMs : "Q : Help me calculate the problem of a chicken and rabbit in the same cage. There are chickens and rabbits in the cage, with a total of 100 feet. How many rabbits and how many chickens are there?" mixtral assumes the premise that there are 35 animals. The correct answer to this question should actually be the missing condition (total number of animals)