Open mhostetter opened 5 months ago
Is it rng.normal(size=trials, scale=np.sqrt(n0 / 2)) or rng.normal(size=trials, scale=np.sqrt(n0))?
rng.normal(size=trials, scale=np.sqrt(n0 / 2))
rng.normal(size=trials, scale=np.sqrt(n0))
For real signals, the noise variance is n0/2. There's probably a bug somewhere, then.
Is it
rng.normal(size=trials, scale=np.sqrt(n0 / 2))
orrng.normal(size=trials, scale=np.sqrt(n0))
?