Closed rubenpieters closed 6 days ago
@ahejlsberg this is a co-effort with @jack-williams that looks very promising. Thoughts?
Silly question but,
Will this also narrow ~T
~ x
to "t"
and "f"
?
What about the more generalized narrowing of T
from an arbitrary discriminated union type?
Taking @keithlayne 's example from Gitter,
interface Foo {
a: number
b: string
c: boolean
}
declare const foo: 'a' | 'b' | 'c'
function f<T extends typeof foo>(x: T, y: Foo[T]) {
if (x === 'a') {
x // T extends "a" | "b" | "c"
}
}
Would be nice if ~T
~ x
is narrowed to "a"
.
Of course, we can't narrow y:Foo[T]
here (unsound)
@AnyhowStep
Narrowing the type parameter T
to "t"
or "f"
is unsound.
Consider this situation:
function f<T extends "t" | "f">(x: T, y: T) {
if (x === 't') {
y // has type "t", but can possibly be inhabited by "f"
}
}
@rubenpieters
In more traditional programming language theory, the knowledge added is very similar to adding a lower bound
"t" <: T
into the context.
According to what @jack-williams told me in another issue, it's not necessarily sound to narrow to T super "t"
in this case either (and you seem to acknowledge as much by saying "very similar"): can you give me an example of when lower-bounding wouldn't be sound?
My bad. I meant narrow x. Sorry! Brain fart
@fatcerberus
It is similar to lower bounds, in that the bound is applicable only in a very limited scope: the indexed access type of a function return type.
Adding a lower bound into the context can be problematic in scenarios similar as described in the Non-Return Indexed Access
section. But this is dependent on the rules of how the simplification of indexed access works. So possibly for TypeScript there wouldn't be an issue.
Adding the general form of lower bounds seem more complicated without enabling interesting use cases, compared to keeping the bounds limited in checking the return statement. Plus, adding lower bounds in this way breaks parametricity.
@AnyhowStep
That seems ok on first sight. But I'm not sure if this should be part of this proposal.
What about the more generalized narrowing of T from an arbitrary discriminated union type
That is something I would like to investigate as well.
It's probably better not to think of these as 'true' lower-bounds on the type, rather a lower bound on the type's behaviour as a set of keys.
When we see str === "t"
, we don't know that T
is lower-bounded by "t"
, but we do know that the set of keys denoted by T
include "t"
. It's a weaker statement but sufficient for refining indexed access types because they only care about T
as a set of keys.
@AnyhowStep
Narrowing x
would be sound but comes with additional technical challenges and it doesn't help us assign a value to F[T]
(unless we are returning something like f[x]
).
When we see str === "t", we don't know that T is lower-bounded by "t"
Don’t you, though? I mean, yes, you can manually instantiate the generic using an unrelated type and then cast, but that’s already unsound in so many other ways that I don’t think we need to account for it at that point.
If there’s a case I’m missing where full lower-bounding would make a valid instantiation unsound, please enlighten me, I’m all ears! 👂
@fatcerberus
I don't think lower bounds by themselves create unsoundness. The problem arises when creating interaction between lower bounds and the indexed access simplification.
For example in the example below, imagine we add the lower bound "t" <: T
in the if-branch. This is ok by itself, but does not let us typecheck the return-statement. For this to work we need to add a rule which allows us to do something like: given a lower bound "t" <: T
, then F[T]
simplifies to number
. However, this is problematic as the type of the variable ft
also gets simplified, which is unsound. So, having the interaction between a lower bound and indexed access simplification be applicable everywhere creates unsoundness.
function depLikeFun<T extends "t" | "f">(str: T, ft: F[T]): F[T] {
if (str === "t") {
const n: number = ft; // ft would be simplified to `number`, but can be `boolean`
return 1;
} else {
return true;
}
}
let x: boolean = false;
depLikeFun<"t" | "f">("t", x); // ft can be of type 'boolean'
I think for the initial proposal we would only look at invoking narrowing for specific forms of return type, but ideally we would be more liberal and handle cases like:
const enum Flags {
On,
Off
}
interface FlagLights {
[Flags.On]: 'green';
[Flags.Off]: 'red';
}
interface FlagText {
[Flags.On]: 'on';
[Flags.Off]: 'off';
}
function getToggleProps<T extends Flags>(flag: T): { colour: FlagLights[T]; text: FlagText[T] } {
switch (flag) {
case Flags.On:
return { colour: 'green', text: 'on' };
case Flags.Off:
return { colour: 'red', text: 'off' };
}
}
Indeed. If we do want to handle narrowing of generic indexed access inside a structure, we do have to take care to only handle the positive positions. Otherwise we get the same problem as I mentioned above.
function depLikeFun<T extends "t" | "f">(str: T): (ft: F[T]) => F[T] {
if (str === "t") {
return (ft: number) => { // should be rejected
return 1;
};
} else {
return (ft: F[T]) => {
return true;
};
}
}
depLikeFun<"t" | "f">("t")(true); // ft can be `boolean`
After experimenting more with this, I feel that limiting the implementation to the checkReturnStatement
is something that will be too brittle to work for more complex cases. For example, the type of use case @jack-williams pointed where the indexed access is nested inside the return type.
Therefore, I suggest to focus the implementation inside the getSimplifiedIndexedAccessType
function instead. On first sight this might bring along some problematic interactions, but I think there are proper solutions for them.
Let's focus on this function which gathers the essence of these interactions:
function f<T extends "t" | "f">(
t: T,
t2: T, // second key which we do not test
ft: F[T], // a value of type F[T]
f: F, // a record of type F
) {
if (t === "t") {
const n: number = ft; // a) should be rejected, ft can be bool
f[t2] = 1; // b) should be rejected, f[t2] can be bool
return 1; // c) should be accepted
}
throw "";
}
This use case shows three scenarios, two of which should be rejected and one which should be accepted. Scenario A showcases that the variance is important when doing the simplification for this proposal, this information is already part of the getSimplifiedIndexedAccessType
function which I think we can reuse. Scenario B is a bit more problematic, but it is possible to resolve this problem using something like #33089 , which assigns a specific write indexed access type to the lhs of the expression f[t2] = 1
. Scenario C is the normal operation of the extension, and since the implementation is located in the getSimplifiedIndexedAccessType
it naturally extends towards checking indexed access inside nested structures as well.
Any thoughts / comments are welcome.
Function overloading provides a functional workaround.
Since depLikeFun
return type is dependent of its parameters type, the function type can be:
{
(str: "t"): number;
(str: "f"): boolean;
}
And it can be safely defined this way:
type K = string | number | symbol;
const keyIs = <k extends K, C, T extends { [i in k]: unknown; }, V extends { [i in k]: C; }>(
args: T | V, k: k, c: C): args is V => args[k] === c;
function depLikeFun(str: "t"): F["t"];
function depLikeFun(str: "f"): F["f"];
function depLikeFun(...args: ["t"] | ["f"]) {
if (keyIs(args, 0, 't' as const)) {
return 1 as number;
} else {
return true as boolean;
}
}
const myNumber = depLikeFun('t'), myBoolean = depLikeFun('f');
@miginmrs This is covered in the Workaround section.
As far as I can see, your workaround is unsafe as mentioned. The compiler does not prevent incorrect implementations of depLikeFun
, essentially reverting back to pre-3.5 behaviour. If we swap the 1
and boolean
return values in your example, the compiler does not complain. Playground link.
@rubenpieters Thank you for the note, I didn't notice this before. By the way, I am still thinking for a workaround by the time the feature is implemented, it could be ugly, but this is the best I could:
type depLikeFun<arg, T> = typeof depLikeFun extends { (x: arg): T; } ? T : never;
function depLikeFun(str: "t"): F["t"];
function depLikeFun(str: "f"): F["f"];
function depLikeFun(str: "t" | "f") {
if (str === 't') {
const ret: depLikeFun<typeof str, number> = 1;
return ret;
} else {
const ret: depLikeFun<typeof str, boolean> = true as boolean;
return ret;
}
}
const myNumber = depLikeFun('t'), myBoolean = depLikeFun('f');
@miginmrs Actually, I think you can simplify your depLikeFun
type with just F[typeof str]
. Then it becomes this:
function depLikeFun(str: "t"): F["t"];
function depLikeFun(str: "f"): F["f"];
function depLikeFun(str: "t" | "f") {
if (str === "t") {
const ret: F[typeof str] = 1;
return ret;
} else {
const ret: F[typeof str] = true as boolean;
return ret;
}
}
It requires the discipline of annotating the return type with this expression to prevent mistakes, but is the neatest workaround I've seen so far.
Code
in this case
Type Guards can work by isKnownLifecycleKey
but Type Guards can't work by in
export declare const lifecycleMap: {
install: {
readonly name: "install";
readonly before: readonly ["preinstall"];
readonly after: readonly ["postinstall", "prepublish", "prepare", "preshrinkwrap", "shrinkwrap", "postshrinkwrap"];
};
pack: {
readonly name: "pack";
readonly ignoreSelf: true;
readonly before: readonly ["prepublish", "prepare", "prepack"];
readonly after: readonly ["postpack"];
};
publish: {
readonly name: "publish";
readonly before: readonly ["prepublish", "prepare", "prepublishOnly", "prepack", "postpack"];
readonly after: readonly ["postpublish"];
};
};
export interface ILifecycleEntry
{
readonly name: string;
readonly ignoreSelf?: boolean;
readonly before: readonly string[];
readonly after: readonly string[];
}
export type ILifecycleMapKeys = keyof typeof lifecycleMap;
export type ILifecycleMap<K extends string = string> = typeof lifecycleMap & Record<string, ILifecycleEntry>;
export function getLifecycle1<K extends ILifecycleMapKeys>(scriptName: string | K)
{
if (isKnownLifecycleKey(scriptName))
{
return lifecycleMap[scriptName]
}
return (lifecycleMap as ILifecycleMap)[scriptName]
}
export function getLifecycle2<K extends ILifecycleMapKeys>(scriptName: string | K)
{
if (scriptName in lifecycleMap)
{
return lifecycleMap[scriptName]
}
return (lifecycleMap as ILifecycleMap)[scriptName]
}
function isKnownLifecycleKey<K extends ILifecycleMapKeys>(scriptName: string | K): scriptName is ILifecycleMapKeys
{
return scriptName in lifecycleMap
}
Expected behavior:
Actual behavior:
TS2536: Type 'string | K' cannot be used to index type '{ install: { readonly name: "install"; readonly before: readonly ["preinstall"]; readonly after: readonly ["postinstall", "prepublish", "prepare", "preshrinkwrap", "shrinkwrap", "postshrinkwrap"]; }; pack: { readonly name: "pack"; readonly ignoreSelf: true; readonly before: readonly ["prepublish", "prepare", "prepack"]; readonly after: readonly ["postpack"]; }; publish: { readonly name: "publish"; readonly before: readonly ["prepublish", "prepare", "prepublishOnly", "prepack", "postpack"]; readonly after: readonly ["postpublish"]; }; }'.
Playground Link:
Any progress or plans on this issue @ahejlsberg @RyanCavanaugh? This is still holding us back on TS 3.4 😭 From what I understand, the only workaround is a bunch casting everywhere. For us, that's going to be over 1000 places and surely going to introduce some mistakes.
Thanks for the help!
Was this partially enabled by https://github.com/microsoft/TypeScript/pull/43183?
Was this partially enabled by #43183?
No. This issue is about value narrowings causing follow-on effects to how we reason about the type parameters themselves.
I see, #43183 only narrows down the value itself, not the type, makes sense, thanks for replying.
I came to report a similar issue and think it's a duplicate of this, so I'll put the example function here:
const getFirstTwoLetters = function<T extends string | undefined> (
strIn : T
) : T {
if(typeof strIn === 'undefined') {
return strIn;
}
//At this point in execution, TypeScript knows strIn is of type string.
//It should also be able to figure out that T is of type string,
//with no undefined option.
return strIn.substring(0, 2);
}
The error thrown on the last line is TS(2322):
Type 'string' is not assignable to type 'T'. 'string' is assignable to the constraint of type 'T', but 'T' could be instantiated with a different subtype of constraint 'string | undefined'.
By the point that return statement is reached, 'T' could NOT logically have been instantiated with a different subtype of that constraint.
@wbt To give one obvious edge-case:
const a = getFirstTwoLetters<"abcd">("abcd");
Your generic signature says this would return "abcd"
, but it returns "ab"
. This is what TS is warning you against. If you remove that .substring(0, 2);
, the error goes away as well.
I recently asked the following Stack Overflow question, and was directed here.
The gist of it, I tried to do the following and all the returns were considered not valid:
interface Obj {
foo: number;
bar: string;
}
function createValueOfObjKey<Key extends keyof Obj>(key: Key): Obj[Key] {
switch (key) {
case "foo":
return 0;
case "bar":
return "";
}
}
Now, further into development I ran into additional issues, and wanted to ask if the following is also related to the topic at hand.
Let's suppose the above function (function createValueOfObjKey<Key extends keyof Obj>(key: Key): Obj[Key]
) worked, disregarding implementation details. Now, I wrote this function, for TypeScript to be able to guarantee me, that the return value is assignable to the given key. I've found that this only works if it's done "statically", meaning, the exact variant is known.
Consider the following example:
interface Obj {
foo: number;
bar: string;
}
type ObjKeyValTuple<Key extends keyof Obj> = Key extends Key ? [Key, Obj[Key]] : never;
// "Static" — works
{
const staticTupleValid: ObjKeyValTuple<"foo"> =
// Correct: no error.
["foo", 0];
const staticTupleInvalid: ObjKeyValTuple<"bar"> =
// Correct: complains about invalid value.
["bar", 0];
}
// "Dynamic" — does not work
{
// Simulating dynamically getting key, e.g. parsing input.
// Cast required, as removing it leads to TypeScript narrowing the type
// to the specified variant.
const key: keyof Obj = "foo" as keyof Obj;
const value = getValue(key, "1");
const dynamicTuple: ObjKeyValTuple<typeof key>
// Incorrect: complains but should work.
= [key, value];
// Simulating dynamically getting value, e.g. parsing input
// The function guarantees that the returned value is assignable to the
// property `Key` (passed as parameter `key`) in `Obj`.
function getValue<Key extends keyof Obj>(key: Key, input: string): Obj[Key] {
switch (key) {
case "foo":
// The casts are needed because of the present issue.
return parseInt(input) as Obj[Key];
case "bar":
return input as Obj[Key];
}
// This is for some reason also required, because exhaustive checks
// are not workings...
throw new Error("unreachable");
}
}
If I get this right, even the examples lack this feature: TypeScript: Documentation - Conditional Types.
Thus, the given function createLabel
cannot be implemented without error:
function createLabel<T extends number | string>(idOrName: T): NameOrId<T> {
throw "unimplemented";
}
and this will fail (without ts-expect-error or explicit cast to any
):
function createLabel<T extends number | string>(idOrName: T): NameOrId<T> {
if (typeof idOrName === "number") {
// @ts-expect-error
return { id: idOrName };
}
// @ts-expect-error
return { name: idOrName };
}
See also TypeScript Playground.
I believe I just ran into a case where this would apply:
type DataNameMap = {
string: string;
number: number;
};
type DataTranslationMap = {
string: DataNameMap["number"];
number: DataNameMap["string"];
};
type DataTranslationObject = {
[key in keyof DataNameMap]: {
arg: {
to: key;
data: DataTranslationMap[key];
};
res: DataNameMap[key];
};
};
type DataTranslationUnion = DataTranslationObject[keyof DataTranslationObject];
function dataTranslation<O extends keyof DataTranslationObject>(arg: {
to: O;
data: DataTranslationObject[O]["arg"]["data"];
}): DataTranslationObject[O]["res"] | undefined;
function dataTranslation<U extends DataTranslationUnion>(
arg: U["arg"]
): U["res"] | undefined {
if (arg.to === "number") {
return Number.parseInt(arg.data);
}
if (arg.to === "string") {
return arg.data.toString();
}
return undefined;
}
I believe the overloading and maybe more could be removed if this was implemented, because I only had to add it to link the return type to the argument type. Otherwise, just the union worked fine.
Coincidentally, even though all the possibilities are covered, the function still needs an ending return statement. Not sure if this is intended, and how to work around it if it is? I would prefer if that undefined
could be removed, based on the fact that another return will always be reached.
What's the current status?
@darrylnoakes
Coincidentally, even though all the possibilities are covered, the function still needs an ending return statement. Not sure if this is intended, and how to work around it if it is? I would prefer if that
undefined
could be removed, based on the fact that another return will always be reached.
TypeScript flow doesn't check if
statement for case exhaustion, but does so for the switch
statement. So this has no error on the return:
function dataTranslation<O extends keyof DataTranslationObject>(arg: {
to: O;
data: DataTranslationObject[O]["arg"]["data"];
}): DataTranslationObject[O]["res"] | undefined;
function dataTranslation<U extends DataTranslationUnion>(
arg: U["arg"]
): U["res"] {
switch (arg.to){
case "number": return Number.parseInt(arg.data);
case "string": return arg.data.toString();
}
}
@craigphicks I don't think there is anything different between if
and switch
statements. I guess your code works because there are function overloads which will bypass some checks.
@jindong-zhannng
These examples, not using overloads, are better:
declare const x: 1|2;
function f2(): 1|2|undefined {
switch (x){
case 1: return x;
case 2: return x;
}
x; // error - unreachable code detected (but type is displayed as "never"
}
function f3(): 1|2|undefined { // error - not all code paths return a value
if (x===1){
return x;
}
if (x===2){
return x;
}
x; // (not unreachable error) type is displayed as "never"
}
So they are both exhaustive with respect to the type, because in both cases the type is displayed as never
.
However, with respect to reachability, the switch
statement is exhaustive and the if
statements are not.
I didn't make that clear in my previous post so thank you for pointing it out.
function f3(): 1|2 { // error - not all code paths return a value
if (x===1){
return x;
}
if (x===2){
return x;
}
return assertNever(x); // (not error) (type is shown as never)
}
function assertNever(value: never): never {
return value;
}
Search Terms
generic indexed access type dependent function generic narrowing
Suggestion
TypeScript does not provide dependent types, but by combining various features such as unions, literal types and indexed access types we can obtain fairly similar behaviour to a dependent function from the caller point of view. Unfortunately, the implementer of such functions is faced with either the possibility of creating unsoundness (pre 3.5) or forced to assert the return type with unsound features (post 3.5). There are some differences with typical dependent functions, which is why we call these dependent-type-like functions.
This suggestion proposes an addition to the typechecking part of TypeScript, which aids the programmer in writing dependent-type-like functions. The main attractive point of this suggestion is that it does not introduce any additional syntax, and is meant to be a conservative extension. Thus it is not a breaking change with regards to the changes introduced in 3.5, but it does enable certain sound scenarios to typecheck.
Use Case
The main use case is dependent-type-like functions, the
depLikeFun
example is a minimalistic scenario showcasing such a situation. In this example, we have thedepLikeFun
function which returnsnumber
when its input is of type"t"
andboolean
when its input is of type"f"
.This pattern occurs in various places, such as the TypeScript dom bindings, in issues such as #31672 and #32698, in comments of related issues such as #13995, or on stackoverflow questions. This extension could serve as a workaround for related issues such as #22609 and #23861.
Problem
The problem lies in the implementation of the function. The pre-3.5 behaviour enabled the creation of unsoundness in these type of functions. TypeScript checked the return value using the constraint of key type
T
, simplifyingF[T]
tonumber | boolean
. However, this is unsound since the caller can provide a more specific type forT
such as"t"
.The post-3.5 behaviour also isn't satisfactory for this use case. It disallows the
depLikeFun
to be implemented, which means the implementer needs to use unsafe type assertions. By #30769, assigning to typeF[T]
is interpreted as a write toF
at keyT
. This means that the result typeF[T]
is checked against the intersection of its possibilities, which isnumber & boolean
and thusnever
.Mistakes are more likely to occur in complex situations, and thus aiding the user with these types of functions seems in line with TypeScript's design goals.
Examples
In a dependently typed language
depLikeFun
would be modeled asfunction depFun(str: "t" | "f"): F[str]
. There are meaningful differences between depending on the actual value of the input versus the type of an input. This distinction makes this issue more tricky to solve than appears on first sight. In this section we showcase the expected behaviour of the addition on certain representative examples.The main idea behind the addition is as follows: in a dependent-type-like function we cannot narrow the type
T
of a variable when its value is checked. For example, ifstr
has typeT extends "t" | "f"
and we check whetherstr === "t"
, then it is unsafe to narrowT
to"t"
in that branch, sinceT
could also be instantiated with the wider type"t" | "f"
. Instead, we add knowledge about the typeT
within the branch which is more conservative, but makes it possible to allow the behaviour of dependent-type-like functions. In more traditional programming language theory, the knowledge added is very similar to adding a lower bound"t" <: T
into the context.Basic Use Case
First we look at the
depLikeFun
example. In theif
-branch, returning1
is allowed since after checkingstr === "t"
the type ofT
can only be"t"
or"t" | "f"
. Thus, the caller will expect either anumber
ornumber | boolean
, and thus it is safe to return the value1
.Note: The claim above that
T
can only be"t"
or"t" | "f"
is not quite true due to branded types. For example,T
could also be the typeBranded
, defined astype Branded = "t" & {_branded?: any}
. In this case the caller expects a value of typeunknown
, so returning1
is also safe.An example which does not occur for dependent functions, but does occur in dependent-type-like functions, is the following. The type
T
can be attributed to multiple inputs, this possibility is what makes it unsafe to fully narrow the type parameter based on a check of the inputstr
. However, the reasoning above still holds since the added knowledge is true regardless of how many inputsT
is linked to.The extension is conservative, and behaviour of other cases should be the same as in 3.5. However, what might change is the error message users see when implementing dependent-type-like functions. In the situation below, instead of comparing
true
/1
tonever
, they get compared against the simplified indexed access type within each branch. This isnumber
in the then branch andboolean
in the else branch.Non-Return Indexed Access
The type
F[T]
can occur elsewhere in the function. This extension retains the normal TypeScript behaviour in those cases, and is only enabled when checking the return type of a function. In the following example we have a value of typeF[T]
as second input to the function. Within the then branch, this type should not be simplified tonumber
, since it can actually be of typeboolean
. Checking the first input value does not give us any information regarding the second input value, and thus we cannot do any more simplification.Transitive Type Parameters
TypeScript allows an indexed access with a type parameter which has a direct transitive line to a correct bound. For example, it allows
function depLikeFun<T extends "t" | "f", B extends T>(str: B): F[B]
, but disallowsfunction depLikeFun<T extends "t", F extends "f", B extends T | F>(str: B): F[B]
.In these situation it seems safe to let information flow through the transitive chain in both directions. For example, when checking an input of type
B
, we can add knowledge aboutT
. And vice versa for checking an input of typeT
and an input of typeB
.Consistency with Conditional Types
TypeScript provides alternative means of creating type-level functions by using conditional types. Instead of creating the record type
F
, we can create the type constructorF
which provides a similar mapping.Which can be used as seen below.
This raises the question whether the addition of typechecking for dependent-type-like functions should be added for type level functions created with conditional types too, for consistency purposes. Two points worth noting is that: users were never able to implement this behaviour using conditional types (even pre-3.5), and, type level functions with conditional types are not restricted to a domain of string keys which makes things more complex. Nevertheless, we feel it is a point worth bringing up for discussion.
Behaviour with
any
The result of instantiating a dependent-type-like function with the
any
type gives a result ofany
. This occurs, for example, when disabling--strictNullChecks
and calling the function withnull
. Any behaviour related to interaction withnull
/any
and dependent-type-like functions is supposed to be unchanged compared to 3.5.Compiler Changes
In this section we roughly outline the suspected changes to the compiler needed to implement this extension.
checkReturnStatement
(checker.ts) function. When the criteria for enabling dependent-type-like function checking are true, we instantiate the type parameter based on a lookup of checks with literals in the control flow graph. These criteria are currently: the index type is a type parameter, this type parameter is declared in the enclosing function, the index type can be used to index the object type and the object type is concrete.bindWorker
function (binder.ts).Workaround
The current suggested workaround seems to be unsafe type assertions or overloaded signatures, both of which are unsafe features. Neither are satisfactory since the typechecker does not help in preventing programmer mistakes when implementing dependent-type-like functions.
Related Suggestions
The following list gathers related suggestions.
oneof
generic constraint: #25879, #27808 or #30284Complementary to
oneof
constraintsThis proposal has some overlapping use cases with proposals which propose to extend TypeScript with a form of
oneof
generic constraint, as mentioned in point 1. This proposal is not competing with these, but rather should be seen as complementary. Theoneof
proposals suggest a new generic constraint which is more restrictive in which instantiations it allows. However, for many of these use cases this is only part of the solution. In addition to adding this syntax, the typechecker must also take this restriction into account to typecheck the original use cases. This proposal kickstarts the implementation of this additional behaviour by focusing on a more constrained use case which does not need this new constraint. If aoneof
generic constraint is added to TypeScript, the behaviour defined in this proposal can be extended to take this additional constraint into account.Checklist
My suggestion meets these guidelines:
NOTE: (Regarding bullet point 1) The goal of this proposal is to provide more complete typechecking than 3.5, and thus we want to avoid breaking any code compared to 3.5.