Open so1ve opened 1 year ago
Oh, thank you!
Hmm, that's not the behavior I'm seeing. I'm getting individual types for the members of the tuple.
That said, you still can't get rid of toString
, because it's on Object
itself. :) But you can get rid of Array
properties, like forEach
, as demonstrated in that Playground.
Ah I think I'm providing a wrong reproduction. I'll update it later.
Could you please checkout https://github.com/so1ve/cride/blob/main/src/index.ts? Test the following code:
const foo = cride({}, [1, "2"])
This works well when you destruct it like const [a, b] = foo
, but once you change the type to:
type IsomorphicDestructurable<
T extends Record<string, unknown>,
A extends readonly any[],
> = Pick<
T & A,
keyof T | (IsTuple<A> extends true ? NumberKeys<A> : `${number}`)
> &
Omit<A, "at" | "slice">; // here!
It breaks.
weird, it still works...
@Peeja One curious thing I noticed is this: https://www.typescriptlang.org/play?ts=5.0.4#code/PTAEBcHtIG3BLADgZ1AQwE4FMIAsfJoC2OAZpBqACZYDGM6AdlaAK7JYBQtkjy4ocpABMoALygA2gEYANKABEwhQF10qHn3Dde-KWmHyARsLUShwgNycQoO3YB6Afk72DNsM84eI0OElQqeFJSLEojLHAAdywsRmo6BjRmNg4dLUFoAGZxKTlFZTU0VAB5InhwAB4ZeSVVWvIMAFE0WlwFAD50vUk0LOMss0zILOtbe1AvNyyfLyA
For the Omit
case, the type hints differ depending on where you hover (declaration vs. use), whereas they're the same for a virgin tuple type. So there's something different happening with type inference between the two cases that could be causing issues in more complex scenarios.
Ah yes! That's a little bit like what I'm facing. Interesting that both my declaration and use are wrongly typed.
@fatcerberus Huh, that is odd... π
It seems that mapping type will break the tuple type.
@so1ve That's just the same thing I already pointed out above: declaration site shows string | number
, later uses have the proper type: Playground
In this example you can see that a and c is typed correctly but reject and resolve is not.
Found it! The issue seems to happen when one of the tuple type members is assignable to the other. For instance:
declare const bar: Omit<[number, 1], "at">
const [c, d] = bar
// ^?
c;
// ^? number
// β This should be `1`
d;
// ^? number
Instead of 1
, d
was typed as number
, which I would assume TS is reducing from number | 1
. It's easier to see when the elements are functions:
declare const bar: Omit<[(x: number) => void, (x: 1) => void], "at">
const [c, d] = bar
// ^?
// β This should be `(x: number) => void`
c;
// ^? (x: number) => void | (x: 1) => void
d;
// ^? (x: 1) => void
And that kind of makes sense: here, c
is typed as accepting either a number
or specifically 1
; the latter type is just redundant. In fact, if you give them different return types so it's not redundant, you actually get the right type and not a union.
β¦And it's at this point in the writeup that I discover the actual problem (sort of). All you need to do to "fix" this is to change your target to ES2021 or earlier. This problem only appears to occur while targeting ES2022 and ESNext. I have no idea if that's intentional. My gut feeling is that it's a bug, because it seems to behave in ways that can't be right, but I suppose it's possible TS is just expressing something that's new in ES2022 that I'm not thinking of. (I've been surprised beforeβ¦)
Here's the issue reduced to something actually incorrect. Bizarrely, the type of the value changes depending on whether it's called as a function: when it's used in a function call, it picks of the union members, but it somehow picks the wrong one.
declare const bar: Omit<[(x: number) => void, (x: 1) => void], "at">
const [c, d] = bar
// ^?
// β This should be `(x: number) => void`
c;
// ^?
// β This should also be `(x: number) => void`, and it should accept a 2
c(2);
// ^?
d;
// ^?
This problem only appears to occur while targeting ES2022 and ESNext. I have no idea if that's intentional. My gut feeling is that it's a bug, because it seems to behave in ways that can't be right, but I suppose it's possible TS is just expressing something that's new in ES2022 that I'm not thinking of.
This seems unlikely. Tuple types are purely a TS concept; they are plain old arrays at runtime. It seems more likely that something else changed in type inference that causes this indirectly.
In user code, I'd recommend using a newer version of Omit
that is homomorphic:
type MappedOmit<T, K> = { [P in keyof T as P extends K ? never : P]: T[P] };
But yeah the behavior describes seems a little off
This isArrayLikeType(parentType)
check is at fault here:
https://github.dev/microsoft/TypeScript/blob/fbd63e9e43dc4e64184b590fa156002a7be6d47e/src/compiler/checker.ts#L10376
I'm not quite sure how this should be adjusted though. Currently isArrayLikeType
is defined like this:
function isArrayLikeType(type: Type): boolean {
// A type is array-like if it is a reference to the global Array or global ReadonlyArray type,
// or if it is not the undefined or null type and if it is assignable to ReadonlyArray<any>
return isArrayType(type) || !(type.flags & TypeFlags.Nullable) && isTypeAssignableTo(type, anyReadonlyArrayType);
}
In general, tuples and arrays are not always handled in the compiler in various scenarios - one of other things that comes to my mind is that intersections with tuple/array members are not always handled as expected (although that works in this particular scenario). So perhaps a fix here should involve a more general overhaul of how those things are treated within the compiler instead of being an ad-hoc change to satisfy this particular scenario.
Bug Report
π Search Terms
tuple omit property
Searched in Bing and Github issues but I found nothingπ Version & Regression Information
β― Playground Link
Link
π» Code
π Actual behavior
β
c
andd
are bothstring | number
π Expected behavior
a and b should have correct type