Focus to Main application

[praveenvinnakota]

Hi,

Lets say I am in Main window(X) and when I click on button, a new window(Y) is opened. Now, the focus is shifted to the newly opened window(Y).

I want to focus to main window(X) to perform some operation, is there any way with winAppDriver?

Thanks, Praveen.

[anunay1]

You need to create a root session and then switch to that window.

[trashbat]

Here's a Python snippet demonstrating how I would do it, the principle is the same for C# or whichever binding you're using:

# Open MS Edge (seems reasonable to assume it's installed due to minimum system requirements of WinAppDriver)
desired_caps = {"app": "MSEdge", "ms:waitForAppLaunch": "25"}

driver = webdriver.Remote(command_executor='http://127.0.0.1:4723', desired_capabilities=desired_caps)

# Store the initial window handle
initial_handle = driver.current_window_handle

edge_main_window = driver.find_element_by_tag_name("Window")

# Browse to Google, just so we can differentiate between windows
address_bar = edge_main_window.find_element_by_class_name("OmniboxViewViews")
address_bar.send_keys("https://google.com" + Keys.ENTER)

# Open a new window
edge_main_window.send_keys(Keys.CONTROL + "n")

# Now we have two windows open, with the focus on the new window. Switch back to the original Google window:
driver.switch_to.window(initial_handle)

[praveenvinnakota]

Hi, Here is my scenario:

I have created a session for "Party Poker" and now I have clicked on button, which will open a new window(Amsterdam 70) under "Party Poker". Please refer the screenshot for reference. I am not able to switch my session from "Party Poker" to "Amsterdam 70" window, its throwing a "f0da4 is not a top level window handle" error. Also, please find the below code for reference:

_cap.setCapability("app", "Root"); desktopsession = new WindowsDriver(new URL("http://127.0.0.1:4723"), cap); System.out.println("Title : " + desktopsession.getTitle()); - This will get Desktop1

String topWindow = desktopsession.findElementByXPath("//[contains(@Name, 'Party Poker')]").getAttribute("NativeWindowHandle"); int MAWinHandleInt = Integer.parseInt(topWindow); String MAWinHandleHex = Integer.toHexString(MAWinHandleInt); cap.setCapability("appTopLevelWindow", MAWinHandleHex); DesiredCapabilities caps = new DesiredCapabilities(); caps.setCapability("appTopLevelWindow", MAWinHandleHex); session = new WindowsDriver(new URL("http://127.0.0.1:4723"), caps); System.out.println("Lobby title : " + session.getTitle()); - This will get Party Poker topWindow = desktopsession.findElementByXPath("//[contains(@Name, 'Amsterdam 162')]").getAttribute("NativeWindowHandle"); MAWinHandleInt = Integer.parseInt(topWindow); MAWinHandleHex = Integer.toHexString(MAWinHandleInt); session.switchTo().window(MAWinHandleHex); - Here its throwing error.._

[anunay1]

What if you don't use the switch to option

[praveenvinnakota]

What if you don't use the switch to option

Its able to reconize the controls, but the problem here is, later I will open another window which will have window name="France 123".. and now I have 2 windows (Amsterdam 162 & France 123) and now if I try to find the control (lets say button 'Fold', this button will be there in both the windows). So, I am not sure in which window it will try to find the control.. thats the reason I want the create individual sessions to be created for both these windows.

[praveenvinnakota]

Hi Any update on the above issue :

I have created a session for PW window and started the script, lets say if I have 2 child windows (ABC & XYZ) under the parent window (PW). Is there a way to switch to ABC window, so that I can perform actions on this window. Idea here is to if I am able to switch ABC window, I need to switch XYZ window as well to perform actions on this screen.

Please.. any update on this issue is highly appreciated?

Thanks in advance, Praveen.

[trashbat]

If you can send me a minimal example of what you have already then I'll take a look, although I can't make any promises!

[trashbat]

P.S. I've just noticed that I'm tagged as a contributor to WinAppDriver, I just contributed a few lines of code to one of the sample tests that wasn't working for UK keyboard layouts.

[praveenvinnakota]

Hi John,

Here are the steps:

1 Step:

            cap.setCapability("app", "C:\\Program Files (x86)\\Programs\\Client.Desktop.exe");
    try
    {
        mainsession = new WindowsDriver(new URL("http://127.0.0.1:4723"), cap);
    }
    catch(MalformedURLException e)
    {
        e.printStackTrace();
    }
    mainsession.manage().timeouts().implicitlyWait(5, TimeUnit.SECONDS);

            System.out.println("Title : " + mainsession.getTitle());  // Let's say, here I get title as "MainAppWindow".

2 Step :

          mainsession.findElementByName("ABC")).click();
          Here, I click on a button "ABC", which will open a new window. Let's say window name is : ABC.

           mainsession.findElementByName("XYZ")).click();  (infact some times this action is also failing, because ABC window is in focus and MainAppWindow is back to ABC window)
          And again I click on another button "XYZ", which will open a new window. Let's say window name is : XYZ

          Here, both windows have same controls, just that window name is different.

          **Inspect .exe : MainAppWindow is parent and ABC, XYZ are child windows to MainAppWindow.**

          Now, my requirement is do actions in both the windows. 
          First, I have to click SUBMIT button in ABC window (NOTE : SUBMIT button is also there in XYZ window)
          mainsession.findElementByName("SUBMIT")).click() - This is success 

          Then, I have to focus on XYZ window and click on SUBMIT button (NOTE : SUBMIT button is again present in ABC window as well).
          mainsession.findElementByName("SUBMIT")).click() - This fails, trys to click SUBMIT in ABC window.

Hope, the scenario is clear. My main requirement is how to switch between those windows to do actions.

Thanks, Praveen.

[trashbat]

Thanks Praveen, I'll have a look this evening when I get some free time.

[trashbat]

I simulated your situation with a simple C# WPF application, the main window has two buttons named "ABC" and "XYZ" with the following click handler:

private void Button_Click(object sender, RoutedEventArgs e)
{
    Button clickedButton = (Button)sender;

    Window childWindow = new Window
    {
        Title = clickedButton.Name,
        Height = 100,
        Width = 200,
        Owner = this
    };

    Button submitButton = new Button
    {
        Content = "Submit",
        Name = "Submit",
        Height = 20,
        Width = 100
    };

    Grid grid = new Grid();

    grid.Children.Add(submitButton);

    childWindow.Content = grid;

    clickedButton.IsEnabled = false;
    childWindow.Show();
}

So clicking on a button will create a new window, with the same title as the button. I'm not a .NET developer, I'm sure there are better ways of achieving this.

My Java code contains the following, and all of the buttons are clicked for me:

mainSession.findElementByName("ABC").click();
mainSession.findElementByName("XYZ").click();

WebElement abcWindow = mainSession.findElementByXPath("//Window[@Name='ABC']");
WebElement xyzWindow = mainSession.findElementByXPath("//Window[@Name='XYZ']");

abcWindow.findElement(By.name("Submit")).click();
xyzWindow.findElement(By.name("Submit")).click();