Hope to add a method for calculating the hypotenuse with three parameters : double double.Hypot(double, double, double)

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Hope to add a method for calculating the hypotenuse with three parameters : double double.Hypot(double, double, double) #1449

Open QuarkSoftware opened 1 month ago

QuarkSoftware commented 1 month ago

Hope to add a method for calculating the hypotenuse with three parameters : double double.Hypot(double, double, double), Equivalent to Math.Sqrt(x x + y y + z * z), Simplified double.Hypot(double.Hypot(x, y), z)