Closed ondohotola closed 2 years ago
The fourth no_header
argument of the CSV
function needs to be passed as a boolean. The following query may work as expected.
SELECT psv.c17 AS Code,
csv.c2 AS Reason
FROM CSV('|',unl.psv, AUTO, TRUE) psv,
CSV(',',rejections.csv) csv
WHERE psv.c17 = csv.c1
When the --no-header
option is specified, the header line of rejections.csv
is read as the first record, and it is assumed that the header line was not included in the result-set because there was no line in the unl.psv
where c17
matched the value of c1
in the header line. However, this is just a coincidence and such execution methods do not always return expected results.
Hi,
I have two files, one with variable number of fields, no header and delimited by '|' (psv), and another with two fields, delimited by ',' and with a header (csv).
I would like to join them and have I have experimented a little with
SELECT psv.c17 AS
Code
, csv.c2 asReason
FROM CSV('|',unl.psv
, AUTO, no_header) psv,CSV(',',
rejections.csv
) csv WHERE psv.c17 = csv.c1but is squeals
invalid argument for CSV: cannot be converted as a no-header value: no_header
I can of course use --no-header in the command line and it works in my example because csv.c2 can not be equal to psv.c17, but I wonder if this was possible.
greetings, el