Closed brabbitdousha closed 2 days ago
I tried again with dr.set_flag(dr.JitFlag.VCallRecord, False) & dr.set_flag(dr.JitFlag.LoopRecord, False)
this could be running for more than 10k spp, but much slower
You might want to consider to render an image in multiple loops using different seed.
for i in range(npass):
if i == 0:
image = mi.render(scene, integrator=integrator, spp=spp, seed=i) / npass
else:
image += mi.render(scene, integrator=integrator, spp=spp, seed=i) / npass
You might want to consider to render an image in multiple loops using different seed.
for i in range(npass): if i == 0: image = mi.render(scene, integrator=integrator, spp=spp, seed=i) / npass else: image += mi.render(scene, integrator=integrator, spp=spp, seed=i) / npass
Hi, thanks for the advice, I tried this but the memory is still increasing, so still, not working. Anyway, thanks!
I'll close this for now, it seems to be a duplicate of #1353.
The code that @andyyankai shared should work. Rendering in multiple passes does not increase memory usage.
Summary
Hi, I am using python with mitsuba3, and I need to render a reference image with more than 10k spp, maybe 100k spp. However, with
mi.set_variant("cuda_ad_rgb")
and simply callingmi.render(scene=scene, spp=spp)
won't let me do it due to the limitations of MC samples, I tried to rewrite the render() and put a loop in it like simple.py, but I can only render 14777 spp at most, I think there might be some hardware limitations. However, I think this task is a fundamental requirement, so is there anyway I can render for more than 10k spp?System configuration
System information:
OS: windows CPU: intel i9-13900H GPU: RTX 4060 laptop Python version: 3.9 CUDA version: 12.0 NVidia driver: 550.54.14
Dr.Jit version: 0.4.4 Mitsuba version: 3.5.0